SUMMARY
The total pressure at a depth of 850 meters in seawater is calculated using the formula P = P(initial) + ρgh, where P(initial) is 1.01 x 10^5 Pascals, ρ is the water density of 1000 kg/m³, g is the acceleration due to gravity at 9.8 m/s², and h is the depth of 850 m. The resulting pressure at this depth is 8.33 x 10^6 Pascals. To find the factor by which the total pressure at this depth exceeds atmospheric pressure, the ratio of total pressure to atmospheric pressure must be calculated, leading to a factor of approximately 82.5.
PREREQUISITES
- Understanding of hydrostatic pressure principles
- Familiarity with the formula P = P(initial) + ρgh
- Basic knowledge of units of pressure (Pascals)
- Ability to perform ratio calculations
NEXT STEPS
- Research hydrostatic pressure and its applications in fluid mechanics
- Learn about the properties of seawater and its density variations
- Study the concept of pressure ratios in different fluid contexts
- Explore advanced applications of pressure calculations in engineering
USEFUL FOR
Students studying physics, engineers working with fluid dynamics, and anyone interested in understanding pressure variations in fluids.