Vector addition - Vector Spaces

Click For Summary

Homework Help Overview

The original poster attempts to determine whether a set defined by the condition ab ≥ 0 forms a vector space, specifically testing closure under vector addition.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the original poster's expansion of the vector addition equation and the implications of the terms a1b2 and a2b1. Some suggest looking for counterexamples, while others propose visualizing the problem in a 2D plane to identify potential violations of the closure property.

Discussion Status

The discussion is ongoing, with various suggestions being offered, including numerical testing and considering scalar multiplication. There is no explicit consensus on the approach to take, but multiple lines of reasoning are being explored.

Contextual Notes

Participants note the importance of understanding the definitions and properties of vector spaces, particularly regarding closure and additive inverses, while acknowledging the original poster's uncertainty about how to proceed with the terms in their expansion.

depre87
Messages
8
Reaction score
0

Homework Statement


Show if V is a vector space ([a,b,c]|ab>=0). I'm trying to test whether it is closed under
vector addition.




Homework Equations


v=[a1,b1,c1] w=[a2,b2,c2], v and w satisfy ab>=0
a1b1>=0, a2b2>=0
show (a1+a2)(b1+b2)>=0



The Attempt at a Solution


Got to a1b1 + a2b2 +a1b2 + a2b1 after expanding the above equation. Know a1b1 and a2b2 both >=0 however what do I do with the a1b2 and a2b1? I've attempted trying to factor them into a1b1 and have gotten a1b1[(b2/b1)+(a2/a1)] and know a1b1 >=0 however not sure what to do with the terms in the bracket to further prove whether or not it is closed under vector addition.
 
Physics news on Phys.org
Hi depre87! :smile:

Have you tried searching a counterexample?
 
I just had a look and I don't understand it enough to apply it to my question, could you enlighten me? thanks for the suggestion though.
 
Just try some numerical values of v and w and see if you can come up with a counterexample...
 
one way you could do it is to picture a & b in a 2D plane, the allowable areas are a&b both +ve, or both -ve. Now try and think of a vector addition that will take you outside of the allowable areas (the a&b axes may be a good start)
 
Look at scalar multiplication rather than addition. If v is such a vector, what is (-1)v?

Or, similarly, every vector must have an additive inverse.
 
Last edited by a moderator:

Similar threads

  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 61 ·
3
Replies
61
Views
5K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 4 ·
Replies
4
Views
15K
  • · Replies 8 ·
Replies
8
Views
2K