Vector analysis homework question

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Homework Help Overview

The discussion revolves around a problem involving three charged particles arranged in a right-angled triangle, focusing on calculating the net force acting on one of the charges using vector analysis and the cosine law.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the net force on charge q1 by applying the cosine law to the forces exerted by charges q2 and q3. Some participants question the origin of the angle used in the cosine law and the correctness of the formula applied.

Discussion Status

The discussion is ongoing, with participants exploring the setup of the free body diagram (FBD) and questioning specific assumptions about the angle and the application of the cosine law. No consensus has been reached yet.

Contextual Notes

Participants are working within the constraints of homework guidelines, which may limit the type of assistance provided. The original poster's calculations and assumptions are under scrutiny.

chemboy
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3 electrons q1, q2, q3 setup in a right angled triangle

q1
|\
| \
q3-q2

charges are

q1 = +2.5 X 10^-17C
q2 = +3.0 X 10^-17C
q3 = +3.5 X 10^-17C

distances between the charges
q1-q3 = .03 m
q1-q2 = .05 m

setup FBD

\
\ 2F1
\
/
/ 3F1
q1

2F1 = k*q1*q2 / .05^2
= 2.7 X 10^-21N
3F1 = k*q3*q1 / .03^2
= 8.75 X 10^-21N

now I think I use cosine law to figure this out

Fnet = 2F1^2 + 3F1^2 - 2(2F1)(3F1)cos45

is this going the right direction, or did I screw up my FBD
 
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find the magnitude and direction of the force acting on q1
 
chemboy said:
now I think I use cosine law to figure this out

Fnet = 2F1^2 + 3F1^2 - 2(2F1)(3F1)cos45

is this going the right direction, or did I screw up my FBD

Hi chemboy! :smile:

erm … where did 45º come from?

And are you sure that minus should be there? :smile:
 
Thread moved to Homework Help forums.
 

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