Vector circulation. Stokes, Gauss and maybe more?

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AlfredB
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Hello. My first time posting here. So... My question is kinda hard to explain but I will try to. So we all know about the Kelvin-Stokes theorem (not talking about manifolds here) :
Kelvin-Stokes theorem: the surface integral over Sigma of the curl of F dot dSigma equals the line integral around boundary dSigma of F dot dr.

And we also know about Ostrogradsky/Gauss Theorem :
Triple integral over volume V of the divergence of vector field F, dV, equals (left side of the equation, shown as a triple integral sign with subscript V).
[PLAIN]http://upload.wikimedia.org/wikipedia/commons/thumb/8/86/OiintLaTeX.svg/23px-OiintLaTeX.svg.png[PLAIN]http://upload.wikimedia.org/math/a/b/9/ab9fd5a4aaa36e402c98cbd36af3a70d.png

I don't have a problem with these 2. I perfectly get them. What bothers me is: can there be found a relationship between the circulation of a vector
Equation: closed line integral of vector field v dot dr around a closed contour equals 0, shown as a loop integral symbol over a closed path.

and the volume integral ? Just like Stokes relates circulation and curl and Gauss relates flux and div . Now how can a contour enclose a volume ? If you can modify is shape you can(see my attachment ) THat's just an idea, I don't know if it's been done or it can be done. And while you can modifiy the shape of the contour to get different surfaces of different areas you can only get one sphere of only one volume, speciffic to the length of the contour. I'm sorry if I was inchorent, just ask me if you want me to try and formulate my question in a different way although I tried to explain it as good as I could.
 
Attachments
  • Closed curve drawn inside a circle, shaped like a lens or vesica, with its two lobes touching the outer circle at top and bottom.
    1.png
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Circulation about what loop? A three dimensional object may have a well defined two dimensional surface but there are infinitely many one dimensional loops lying in that surface. (I'm not clear what you picture is supposed to show but it is certainly not a curve completely covering the sphere.)