The vector equation of a line parallel to the vector 2i-10j-8k and passing through the point (5, -1, 6) is expressed as r = (5i - j + 6k) + λ(2i - 10j - 8k), where λ represents a scalar parameter. This formulation confirms that the line maintains its direction defined by the vector while originating from the specified point. The discussion clarifies the use of the Greek letter lambda (λ) in vector equations, which denotes the scalar multiple in the equation.
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lemon said:1. Determine the vector equation of the line which is parallel to the vector 2i-10j-8k and which passes through the point (5, -1, 6).
2. vector equation
3. 2i-10j-8k (5, -1, 6)
5i-j+6k+landa(2i-10j-8k)
Is this all I need to do to complete this question, please?
I don't see an equation - an equation always has = in it. Also, this Greek letter - [itex]\lambda[/itex] - is named "lambda."lemon said:Determine the vector equation