Vector function, position and tangent vectors

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Maianbarian
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Homework Statement


If a curve has the property that the position vector r(t) is always perpendicular to the tangent vector r'(t) show that the curve lies on a sphere with center at the origin


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The Attempt at a Solution



I have no idea how to even approach this problem, if somebody could give me a nudge in the right direction it would be much appreciated.
 
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Ah, I get it now.

We know that r(t).r(t)=|r(t)|^2. Differentiating the dot product we get:

d/dt [r(t).r(t)]= 2r'(t).r(t) = 0 (as r'(t) is orthogonal to r(t))

thus |r(t)|^2 is constant, and so |r(t)| is constant, which corresponds to a sphere with the centre at the origin.

Thanks Dick :)