(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

With O as the origin, the points A,B,C have position vectors

i,i+j,i+j+2k

respectively, Find a vector equation of the common perpendicular of the lines AB and OC.

Show that the shortest distance between the lines AB and OC is [itex]\frac{2}{5}\sqrt{5}[/itex]

Find,in the form ax+by+c=d, an equation for the plane containing AB and the common perpendicular of the lines AB and OC.

2. Relevant equations

Vector formulae.

3. The attempt at a solution

OA=i

OB=i+j

OC=i+j+2k

AB=AO+OB=j

the direction of the common perpendicular is ABxOC =2i-k

But to get the vector equation I need a point on the line. How do I find that?

(Also, I was never really taught how to do these sorts of vector problems, only ones at AS math level)

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# Homework Help: Vector help(Planes and normals)

Can you offer guidance or do you also need help?

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