Vector (i-j=k): Why Does MA=i+j+k?

  • Thread starter Thread starter desmond iking
  • Start date Start date
  • Tags Tags
    Vector
Click For Summary
SUMMARY

The discussion centers on the vector equation MA = i + j + k, specifically addressing the confusion surrounding the cross product of vectors (i - j) and (i + j). The calculations presented demonstrate that (i - j) × (i + j) results in 2k, confirming that the initial interpretation of the vector MA is incorrect. The correct approach involves recognizing the contributions of the cross products and their resultant vectors, leading to the conclusion that the magnitude of the vector is indeed half of what was initially proposed.

PREREQUISITES
  • Understanding of vector operations, specifically cross products.
  • Familiarity with unit vectors i, j, and k in three-dimensional space.
  • Knowledge of vector magnitude and direction concepts.
  • Basic proficiency in mathematical notation and vector equations.
NEXT STEPS
  • Study the properties of vector cross products in detail.
  • Learn how to calculate vector magnitudes and their implications in physics.
  • Explore the geometric interpretation of vector addition and subtraction.
  • Investigate applications of vectors in physics, particularly in mechanics.
USEFUL FOR

This discussion is beneficial for students studying physics or mathematics, particularly those focusing on vector calculus and mechanics. It is also useful for educators seeking to clarify vector operations for their students.

desmond iking
Messages
284
Reaction score
2

Homework Statement


I can't understand why the vector MA finally become (i+j+k) ?? is it beacuse of (i-j ) becomes k ??

Homework Equations

The Attempt at a Solution

 

Attachments

  • kgk.png
    kgk.png
    46.4 KB · Views: 1,131
Physics news on Phys.org
That's wrong!
<br /> (i-j)\times (i+j)=\underbrace{i\times i}_0+i \times j- j\times i-\underbrace{ j \times j}_0=i\times j+i\times j=2 i \times j=2 k<br />
 
  • Like
Likes   Reactions: desmond iking
Shyan said:
That's wrong!
<br /> (i-j)\times (i+j)=\underbrace{i\times i}_0+i \times j- j\times i-\underbrace{ j \times j}_0=i\times j+i\times j=2 i \times j=2 k<br />
It's wrong before that, even.
##\vec P = P(\vec j -\vec k)/\sqrt 2##
Alternatively, by calculating the distance from A to the line of P the moment is seen to have magnitude ##aP\sqrt {\frac 32}##. I believe the correct answer is exactly half that shown.
 
  • Like
Likes   Reactions: theodoros.mihos and desmond iking
-j X i=k
That k and the other normal one from i x j=k, add up to 2k.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
3K
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
25
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K