Vector-Parametric Equation of a Plane

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SUMMARY

The discussion centers on finding a vector-parametric equation of a plane that contains the point (4, -2, 14) and is parallel to the vectors u = 2i - 4j + 7k and v = 3i + 5j - 2k. The vector-parametric equation is expressed as r = a + λu + μv, where 'a' is the point on the plane, and 'u' and 'v' are the direction vectors. The cross product of u and v, calculated as u x v = -27i + 25j + 22k, yields a normal vector to the plane, confirming that the vectors u and v are not parallel to each other, which is essential for defining the plane in three-dimensional space.

PREREQUISITES
  • Understanding of vector operations, specifically cross products.
  • Familiarity with vector-parametric equations of planes.
  • Knowledge of three-dimensional coordinate systems.
  • Basic algebraic manipulation of vector equations.
NEXT STEPS
  • Study the properties of cross products in vector calculus.
  • Learn how to derive the standard form of a plane equation from a normal vector.
  • Explore applications of vector-parametric equations in physics and engineering.
  • Investigate the geometric interpretation of planes in three-dimensional space.
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Students in mathematics or physics, particularly those studying vector calculus, as well as educators looking for examples of vector-parametric equations in three-dimensional geometry.

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Homework Statement


Find a vector-parametric equation of a plane that contains the point (4,-2,14) and is parallel to the vectors u=2i-4j+7k and v=3i+5j-2K.


Homework Equations


Vector Parametric Equation of a Plane: r=a+λu+μv
(if u and v are two non-parallel vectors in the plane)


The Attempt at a Solution


If u and v are parallel to the vector, then wouldn't one of the vectors need to be altered in order for the equation to work? If so, I found the cross product of u and v

u x v= -27i+25j+22k

But would that work? I am unsure whether it is necessary to change u and v in the first place, because I don't know if the vectors can't be parallel to each other, the unfound vector, or the plane itself. Does anyone know how this can be found?
 
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BeanbagxD said:

Homework Statement


Find a vector-parametric equation of a plane that contains the point (4,-2,14) and is parallel to the vectors u=2i-4j+7k and v=3i+5j-2K.


Homework Equations


Vector Parametric Equation of a Plane: r=a+λu+μv
(if u and v are two non-parallel vectors in the plane)


The Attempt at a Solution


If u and v are parallel to the vector, then wouldn't one of the vectors need to be altered in order for the equation to work?
Why would you think this? And what equation are you talking about? You're trying to find the equation of the plane in terms of vectors and a couple of parameters.
BeanbagxD said:
If so, I found the cross product of u and v

u x v= -27i+25j+22k

But would that work? I am unsure whether it is necessary to change u and v in the first place, because I don't know if the vectors can't be parallel to each other, the unfound vector, or the plane itself. Does anyone know how this can be found?
The given vectors are parallel to the plane, but obviously not parallel to each other. That can't happen in R2, where two vectors parallel to a line have to be parallel to each other, but it can happen in R3.

The cross product of your two given vectors gives a vector that is normal to each of them, and hence, to the plane. If you know a point on a plane and its normal, you can find the equation of the plane, either as standard form (ax + by + cz = d) or in terms of the given point and the two vectors.
 
BeanbagxD said:

Homework Statement


Find a vector-parametric equation of a plane that contains the point (4,-2,14) and is parallel to the vectors u=2i-4j+7k and v=3i+5j-2K.


Homework Equations


Vector Parametric Equation of a Plane: r=a+λu+μv
(if u and v are two non-parallel vectors in the plane)

Doesn't your problem exactly fit the relevant equation you have listed?
 

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