Vector - sum of two vectors * some const

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The discussion revolves around finding constants a and b for the equation a*<3, 2> + b*<-2, 3> = <2, 3>. The user attempted to solve the system of equations derived from the vector components but struggled to find a correct solution. They initially used Gaussian elimination but received feedback that their results were incorrect. The user expresses confusion about the problem's requirements and whether they fully understand the question. Clarification on the correct method or approach is sought to resolve the issue.
asdfmaster
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a*<3, 2> + b*<-2, 3> = <2, 3> - A, B?

Homework Statement


There exists a vector <2, 3>.
Said vector is the sum of two other vectors <3, 2> and the orthoginal to <3,2> (which I think is <-2, 3> right?)


Homework Equations


<2, 3> = a<3, 2> + b<-2, 3> where a, b are constants


The Attempt at a Solution


I tried solving the x and y seperately: 2 = a*3 + b*-2 but there's many ways this can be done, none of which held true also for the y.
 
Last edited:
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Maybe I didn't describe it well enough. The problem is that I have a vector <2, 3> and I must get from the origin to (2, 3). I start moving parallel to <3, 2> and make a right angle turn. Where do I make the right angle turn?
 
EDIT:
I take back the above matrix, which I am now deleting. The system you'll need to solve is

<br /> \begin{align*}<br /> 2x + 3y &amp;= 13\\<br /> 2x - 3y &amp;= 0<br /> \end{align*}<br />

Which can be solved via elimination.
 
Last edited:
Well, I just tried elimination using gaussian elimination

Code:
Starting matrix:
2  3    13
2 -3    0

to
2  3    13
0 -6   13

to
1  3/2    13/2
0  1      13/-6

to
1  0    39/4
0  1    13/-6

so I end up with x = 39/4 and y=13/-6
But I asked and he told me that it wasn't correct.
 
asdfmaster said:
Well, I just tried elimination using gaussian elimination

Code:
Starting matrix:
2  3    13
2 -3    0

to
2  3    13
0 -6   13

to
1  3/2    13/2
0  1      13/-6

to
1  0    39/4
0  1    13/-6

so I end up with x = 39/4 and y=13/-6
But I asked and he told me that it wasn't correct.

Has he given you the correct answer? Maybe I don't understand the question completely.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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