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The discussion focuses on a geometry problem involving two lookouts spotting a fire at different bearings. Lookout No.1 observes the fire at a bearing of 050 degrees, while Lookout No.2 sees it at 020 degrees, with a distance of 10 kilometers between the two lookouts at a bearing of 120 degrees. The problem can be solved using the Law of Sines and the Law of Cosines to determine the distances from each lookout to the fire. The consensus is that the problem, while related to vectors, primarily utilizes trigonometric principles for resolution.

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realplayer1
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From Lookout No.1, a fire is spotted on a bearing of 050 degrees. From Lookout No.2, a fire is spotted on a bearing of 020 degrees. Lookout No.2 is 10 kilometers apart from Lookout No.1 on a bearing of 120 degrees. Assuming that the fire and the two lookouts are all on the same horizontal level, find how far the fire is from each lookout.
 
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realplayer1 said:
From Lookout No.1, a fire is spotted on a bearing of 050 degrees. From Lookout No.2, a fire is spotted on a bearing of 020 degrees. Lookout No.2 is 10 kilometers apart from Lookout No.1 on a bearing of 120 degrees. Assuming that the fire and the two lookouts are all on the same horizontal level, find how far the fire is from each lookout.


Welcome to PF. Please click on the rules link above for instructions about how to post homework questions.
 
If it's any consolation, I think this question is dying to be plugged into the Law of Sines and/or Cosines. It's not exactly vector related.
 

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