Four planes intersect in such a way that there is no common point between all four of them but that each set of three has a single common point. The position vectors of the four common points,A,B,C,D are, <-4,-3,-3> ,<7,5,-2>,<1,-2,5>,<-4,6,-1> respectively.
(a) Find the volume enclosed by the four planes. (b) Find the cartesian equations of the four planes.
When I drew this out I got something that reminded me of a tetrahedron. But it looked like there were two of them. So, in general I for part a i just did V = 1/6[abc] + 1/6[abd]
I would write it but I don't have my papers with me.
The Attempt at a Solution
For the Cartesian equations I don't know what to use. Draw the picture and you will see that there are more then 4 faces so it is confusing me. How do I decifer which ones to use?