Velocity and height of an arrow

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the whizz
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would like to see if this looks rite before bed...due tomorrow
 
This is great because I was just having trouble calculating velocity tonight and finally figured it out.

You've got the height right and a short cut I discovered to finding velocity is
that velocity equals the square root of 2xgxh

v=[tex]\sqrt{}2gh[/tex] so v=[tex]\sqrt{}2x9.8x217.55[/tex]

v=65.3m/s