Velocity and mass rate of a rocket.

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Homework Help Overview

The problem involves a rocket that ejects pressurized air with a constant relative velocity while moving horizontally. The original poster seeks to determine the speed of the rocket as its mass decreases from an initial mass to a final mass, and how this speed relates to the rate at which air is ejected.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the rocket's speed using a specific equation and questions how the result is influenced by the mass ejection rate. Some participants suggest considering fixed values for certain variables to clarify the relationship between speed and mass rate.

Discussion Status

Participants are exploring the implications of the rocket equation and its dependence on mass flow rate. Some have provided insights into the continuity equation and questioned the role of mass rate in the overall change in speed, indicating a productive examination of the topic.

Contextual Notes

There is an emphasis on understanding the relationship between the mass flow rate and the rocket's speed, with participants noting that the mass flow rate does not appear in the rocket equation itself under certain conditions. This raises questions about assumptions regarding fixed values of mass and velocity.

AbigailM
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Homework Statement


A rocket ejects pressurized air with constant relative velocity v_{rel} and moves horizontally. Starting from rest and an initial mass m_{1}, find the speed of the rocket when its mass is m_{2}(m_{2}<m_{1}). How does this result depend on the rate r=dm/dt at which the air is ejected?


Homework Equations


v = v_{0}+v_{rel}ln\frac{m_{1}}{m_{2}}

m(t)=m_{1}+\dot{m}t

The Attempt at a Solution



v=v_{rel}ln\frac{m_{1}}{m_{2}} where v_{0}=0m/s

The result depends on the rate in that the velocity increases as m_2 becomes smaller.

How does this look? Thanks for the help.
 
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Your answer to the first question is correct, but you may want to think some more about the second question. You should try to answer that question under the assumption that m1, m2 and vrel all are fixed values.
 
Ok I think I've got something.

From the continuity equation for mass,
\dot{m}=\rho v A where \rho is the density and A is the area.

\dot{m}=\rho Av_{rel}ln\frac{m_{1}}{m_{2}}

Does this look ok?

Thanks!
 
No, it is simpler than you think.

Your original equation (the rocket equation) is correct, i.e. ΔV = V2 - V1 = Ve ln(m1/m2). Now, the question is if this equation depends on the value of the mass rate, that is, assuming that Ve, m1 and m2 all are constant do ΔV then change if dm/dt change, or in other words, do dm/dt appear in the rocket equation at all?

Looking at the rocket equation the answer is obvious, but the result is perhaps a bit surprising given how present dm/dt is in the derivation leading up to the rocket equation. It means, for instance, that a spacecraft will not end up going faster if you increase the accelerating force by putting on an extra (identical) rocket engine but keep the amount of propellant equal. The increased force will be "compensated" by the increased mass flow rate so that the rocket, while accelerating faster, will use its propellant faster and still end up with the same total change in speed. This means that change in speed for a given engine technology (Ve) and mass ratio (m1/m2) is independent of the "size" of the engine and the reasons why the concept of "delta-Vee" is such a useful concept in space mission design.
 

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