Velocity and Total Distance Table for Stone Dropped from Tall Building

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The discussion focuses on constructing a table to calculate the velocity and total distance of a stone dropped from a tall building over the first five seconds. Participants clarify that the correct approach involves using kinematic equations: velocity (V = at) and distance (D = 1/2 at²). There is confusion about the difference between speed and velocity, with participants seeking clarification on these concepts. An example table is provided, showing time, velocity, and calculated distance values for each half-second interval. The conversation emphasizes the importance of understanding these fundamental physics equations for accurate calculations.
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My question I don't understand how to add a colums for total distance.

Construct a table of values of velocity and total distance fallen at the end
of each half-second during the first 5 seconds for a stone at rest dropped
from a very tall building. Include columns for time, velocity, and total
distance


Time of Fall Velocity Aquired Distance
(seconds) (meters/seconds (meters/seconds
_______________________________________
0--------------------- 0---------------------0
0.5-------------------4.9--------------------1.225m/s
1--------------------- 9.8-------------------4.9m/s
1.5-------------------14.7-------------------11.025m/s
2 ------------------- 19.6------------------19.6m/s
2.5------------------24.5--------------------30.625m/s
3 -------------------- 29.4------------------44.1m/s
3.5-------------------34.3-------------------60.025m/s
4--------------------- 39.2------------------78.4m/s
4.5-------------------44.1-------------------99.225m/s
5--------------------- 49--------------------122.5m/s
 
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Originally posted by celect
My question I don't understand how to add a colums for total distance.
I know you know how to find the distance an object falls as a function of time. Use the basic kinematics equation for accelerated motion.

(You won't need to add columns.)
 
Originally posted by celect
My question I don't understand how to add a colums for total distance.

Construct a table of values of velocity and total distance fallen at the end
of each half-second during the first 5 seconds for a stone at rest dropped
from a very tall building. Include columns for time, velocity, and total
distance


Time of Fall Velocity Aquired
(seconds) (meters/seconds
_______________________________________
0--------------------- 0
0.5-------------------4.9
1--------------------- 9.8
1.5-------------------14.7
2 ------------------- 19.6
2.5------------------24.5
3 -------------------- 29.4
3.5-------------------34.3
4--------------------- 39.2
4.5-------------------44.1
5--------------------- 49
total = d=49m
 


Originally posted by celect
total = d=49m
No. What you've done is give a table with columns for time and speed, not distance. I think you need a table with three columns: time, speed, and distance.

V=at

D=\frac{1}{2}at^2
 
I'm hoping someone can help me.

I'm working on this same Velocity table and need to understand a couple things. Is velocity the same as the speed... it should be should it? also, I'm looking for distance and while I have these equations I'm not sure what to do? Physics online is a little more difficult then I realized. But I feel if I get thru the initial reminders of calculus, I'll be just fine.

If someone could do an example even unrelated... it would be sooo helpful. thank you

Using the formulas V=aT & D=1/2aT2

..........V=aT...D=1/2aT2
T2=Time...a or g = Speed m/s... V=Velocity...Distance
0......0......0......0
.5.....4.9.......2.45
1......9.8.......9.8
1.5......14.7......22.05
2......19.6......39.2
2.5......24.5......61.25
3......29.4......88.2
3.5......34.3......120.05
4......39.2......156.8
4.5......44.1......198.45
5......49......245


Is this right so far?
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