Velocity change by force in one and two inertial frame confusion

• JordanGo
In summary: In frame 1, x_1(t) = \frac{1}{2m}Ft^2 + x_1(0) as normal - your professor is leaving off all the subscripts and constants.In frame 2, you have the same derivation - I think that the secret to understanding what he's written is to go through it again yourself, being careful about the constants and the notation.
JordanGo
Hi,
I just finished class and my professor was writing some of Newton's Laws on the board and derived some equations. We ended up with:
V(Δt)=FΔt (this is for velocity in first inertial frame
V(2Δt)=2FΔt (this is for velocity in second inertial frame​
Then he went and got the position in respect with time:
x(Δt)=F(Δt)(Δt) (which is just the integral of velocity in first i.f.)​
But then he did it for the second inertial frame and got:
x(2Δt)=x(Δt)+2F(Δt)(Δt)​

I do not understand where the x(Δt) comes from... Can anyone clarify this for me?

Don't understand your notation ... do you intend $V(\Delta t)$ to mean that $$V$$ is a function of $$\Delta t$$ ?

Perhaps if the context were provided?

Yes, the velocity is a function of time.
When a constant force is applied, the velocity changes with respect to time.

So what could $$F(\Delta t)(\Delta t)$$ ...mean? Or $$F(2\Delta t)$$ ??

The velocity is equal to the force multiplied by the time. When you take the integral of the velocity with respect to time, you get the force times the time squared. Now, for the second inertial frame velocity, I do not understand where he gets the equation (V(2t)). I think he means to generalize it but I'm not sure.

If we write v=at in the first frame, the surely $x=\frac{1}{2}at^2$?

What is the relationship between the frames?

This is murder on a tablet... I'll go get a lappy.

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Lets see... it looks like your professor is ignoring constants on order to focus your attention on the relationships.

Usually, two reference frames are moving with some relative speed.

If the speed of an object in frame 1 is $v_1 = Ft/m$ (because F=ma) then he could be saying that the speed in frame 2 is $v_2(t)=v_1(2t)$ i.e. the same as in frame 1 but with the time axis stretched out.[*] notice how this means that the initial speed of the object is zero in both frames? Is this possible?

... this would mean that $v_2=2Ft/m$ so, the frame 2 observer reckons the force is twice what the frame 1 observer says.

It also means the speed between the frames is $u=v_2-v_1$ ...

In frame 1, $x_1(t) = \frac{1}{2m}Ft^2 + x_1(0)$ as normal - your professor is leaving off all the subscripts and constants.For frame 2, you have the same derivation - I think that the secret to understanding what he's written is to go through it again yourself, being careful about the constants and the notation.

This whole thing has been due to defining all terms in frame 1 and then using them in frame 2.

Not, on the whole, the approach I would have chosen - that goes double if the subject is special relativity ...

-------------------------------

[*] I will try to only use brackets to indicate functions ... part of the confusion came from the use of two different notations in different parts of the same equation.

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What is velocity change by force?

Velocity change by force refers to the alteration in the speed or direction of an object caused by an external force acting upon it.

How does velocity change by force differ in one and two inertial frames?

In one inertial frame, the velocity change by force can be easily calculated using the laws of motion. However, in two inertial frames, the velocity change can be impacted by the relative motion between the two frames and may require additional calculations.

What is an inertial frame?

An inertial frame is a reference frame in which an object at rest remains at rest, and an object in motion continues to move at a constant velocity, unless acted upon by an external force.

What is the relationship between force and velocity change?

According to Newton's second law of motion, the force applied on an object is directly proportional to the acceleration it experiences. Therefore, a greater force will result in a larger velocity change.

Why is understanding velocity change by force important in science?

Understanding velocity change by force is crucial in many fields of science, including physics, engineering, and astronomy. It allows us to predict the motion of objects and design efficient systems and structures that can withstand external forces.

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