Velocity & Gamma Factor of Proton

  • Thread starter Thread starter Abigale
  • Start date Start date
  • Tags Tags
    Proton Velocity
Abigale
Messages
53
Reaction score
0
Hello,

I regard a particle in an accelerator. The particle has the kinetic energy of 7TeV.

I have callculated the momentum $$
E=pc+mc^2\\
\Rightarrow p=\frac{1}{c} \sqrt{E^2 -(mc^2)^2} =7,00094~ TeV/c
$$

After that I want to callculate the "velocity" and the "\gamma-factor".
But I am irritated and don't know which equations are allowed for this relativistic callculations.

For example I have found the equation $$

\vec{p}=m\gamma\vec{v}$$
and
$$
\gamma=\frac{1}{\sqrt{(1-\beta)}}~~~~~~~;\beta=\frac{v}{c}=\frac{pc}{E}
$$


THX
Abby
 
Physics news on Phys.org
If it's the LHC you're talking about, 7 TeV represents the total energy of the particle, not just the kinetic energy.

After that I want to callculate the "velocity" and the "γ-factor".
Try E = γmc2.
 
Abigale said:
I regard a particle in an accelerator. The particle has the kinetic energy of 7TeV.

I have callculated the momentum
$$
E=pc+mc^2\\
\Rightarrow p=\frac{1}{c} \sqrt{E^2 -(mc^2)^2} =7,00094~ TeV/c
$$

That should be
$$
E^2=(pc)^2+(mc^2)^2\\
\Rightarrow p=\frac{1}{c} \sqrt{E^2 -(mc^2)^2} \approx 7 TeV/c
$$

The last assumes that the mass energy is very small compared to 7 TeV. If it's a proton then the mass is 0.938 GeV, which is quite small compared to 7 TeV.

Abigale said:
After that I want to callculate the "velocity" and the "\gamma-factor".
But I am irritated and don't know which equations are allowed for this relativistic callculations.

For example I have found the equation $$

\vec{p}=m\gamma\vec{v}$$
and
$$
\gamma= \frac{1}{\sqrt{(1-\beta)}}~~~~~~~;\beta=\frac{v}{c}=\frac{pc}{E}
$$

Abby

You've got either gamma or beta wrong. I don't know your convention.
$$
\gamma=\frac{1}{\sqrt{(1-\frac{v^2}{c^2})}}
$$

But there's an easier way. The kinetic energy is (\gamma -1) m c^2 = 7 TeV and so you can work out \gamma= (7 TeV - m c^2) / m c^2, and to three digits that's 7460. And then you can work out v. (Assuming I did the arithmetic correctly.)

$$
v = c \sqrt{1-\frac{1}{\gamma^2}} \approx c (1 - \frac{1}{2(7460)^2})
\approx c(1-8.89 \times 10^{-9})
$$
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. The Relativator was sold by (as printed) Atomic Laboratories, Inc. 3086 Claremont Ave, Berkeley 5, California , which seems to be a division of Cenco Instruments (Central Scientific Company)... Source: https://www.physicsforums.com/insights/relativator-circular-slide-rule-simulated-with-desmos/ by @robphy
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
Back
Top