Velocity of a planet around the sun

AI Thread Summary
The discussion focuses on calculating the speed of a planet at its aphelion based on its speed at perihelion, using known distances. The relationship derived shows that the speed at aphelion (va) can be expressed as va = (rp * vp) / ra, where rp and ra are the distances at perihelion and aphelion, respectively. The solution is verified through conservation of angular momentum, confirming the initial calculation. The results align with Kepler's laws, reinforcing the accuracy of the approach. The conversation concludes with affirmation of the correctness of the derived formula.
hs764
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1. Asking because the answer I got seems too simple...a planet of mass m moves in an elliptical orbit about the sun. The minimum and maximum distances of the planet from the sun are called the perihelion and aphelion respectively. If the speed of the planet at p is vp, what is its speed at a? Assume the distances rp and ra are known.

Homework Equations



dA/dt = 1/2r2ω, ω=v/r[/B]

The Attempt at a Solution



dA/dt is constant, so 1/2rp2ωp = 1/2ra2ωa. Substitute v = ωr, that gives 1/2rpvp = 1/2rava, va = rpvp/ra. Is this correct?[/B]
 
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Try verifying the result from another rule - like conservation of momentum and energy...
 
So using conservation of momentum I got the same thing...dA/dt = L/2m = mr2ω/2m. Given that ω = v/r, rpvp/2 = rava/2, va = rpvp/ra.
 
hs764 said:
So using conservation of momentum I got the same thing...dA/dt = L/2m = mr2ω/2m. Given that ω = v/r, rpvp/2 = rava/2, va = rpvp/ra.

Yes, it is the same thing as Kepler's law. Good job.
 
Great, thank you!
 
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