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**1. Anyone interested in looking over the question / coments, thanks. An object mass 0.6kg is fired**

Calculate

A. The velocity of the projectile when it leaves the barrel

B. Height reached by object

c. Time taken from the projectile leaving the gun to return to same height

__vertically upward__in thebarrel of a gun by a vertical force of 50N acting over a period of 0.5 seconds.Calculate

A. The velocity of the projectile when it leaves the barrel

B. Height reached by object

c. Time taken from the projectile leaving the gun to return to same height

**2. a=f/m, V=Vo + AT, V^2=U^2+2AS**

**3. A. First velocity, A=F/M, 50/0.6 = 83.33m/s^2**

Velocity, V=Vo+AT, V=0+83.33 x 0.5 = 41.67ms

B. Height: U=41.67, Vo=0, A=-G = -9.81m/s

0=1736.4-19.62xS

S=1736.4/19.62 = 88.5m

C. S=(T/2)(U+V), 88.5 = T/2 (41.67+0)

T=88.5 x 2 x 2/41.67 = 4.25 seconds

Time to return = 2 x 4.25 = 8.5 seconds

Velocity, V=Vo+AT, V=0+83.33 x 0.5 = 41.67ms

B. Height: U=41.67, Vo=0, A=-G = -9.81m/s

0=1736.4-19.62xS

S=1736.4/19.62 = 88.5m

C. S=(T/2)(U+V), 88.5 = T/2 (41.67+0)

T=88.5 x 2 x 2/41.67 = 4.25 seconds

Time to return = 2 x 4.25 = 8.5 seconds