- #1

pcml100

- 23

- 0

## Homework Statement

A particle of mass 0.000103 g and charge 87 mC moves in a region of space where the

electric ﬁeld is uniform and is 4.8 N/C in the x direction and zero in the y and z direction.

If the initial velocity of the particle is given by v_y = 3.2 × 10^5 m/s, v_x = v_z = 0, what is

the speed of the particle at 0.2 s?

Answer in units of m/s.

## Homework Equations

E = E_x + E_y

a_x = (q/m)E_x

a_y = (q/m)E_y

a = a_x + a_y

v_f = V_0 + at

## The Attempt at a Solution

q = 0.087 C

m = 1.03 * 10^-7 kg

E_x = 4.8 N/C

V_0)y = 3.2 * 10^5 m/s

V_0)x = 0 m/s

V_0)z = 0 m/s

t = 0.2s

a_x = (q/m) E_x = 4054368.932 m/s^2

a_y = 0

a = 4054368.932 m/s^2