Velocity of each ball at the moment of impact: V = u + Ft/m

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SUMMARY

The discussion focuses on calculating the velocity of two heavy balls attached to a light metallic rod at the moment of impact with the ground. The relevant equation derived is V = u + Ft/m, where V represents the final velocity, u is the initial velocity, F is the force acting on the balls, t is the time, and m is the mass of the balls. Key concepts include conservation of linear momentum and energy, with the assumption that friction is negligible. The reaction force from the ground does not perform work on the system, which is crucial for understanding the dynamics involved.

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Homework Statement


Two heavy balls of equal mass M are attached to the long but light metallic rod standing
on the floor. The rod with the balls falls to the floor. Find the velocity of each ball at the moment
when the rod hits the ground. Neglect mass of the rod and the friction between the balls and the
floor.



Homework Equations





The Attempt at a Solution

 
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Conservation of linear momentum may help. Friction is negligible, conservation of energy may also be of help.

A question: Can you explain why reaction force (by the ground) on the ball, touching ground at all moments, does no work on the two-ball system!
 
Last edited:
Equations for Velocity:

1)F=Ma ->
f(a) => V=u+at
2)F=M(v-U)/t

ft=m(V-u)
ft/m+u=V
V=u+ Ft/m
 
Last edited:

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