Velocity of Proton with 23.0 keV Kinetic Energy

[mathcrzy]

Homework Statement

What is the speed of a proton whose kinetic energy is 23.0 keV?

1 eV = 1.6e-19 J
23 Kev = 23000 eV = 3.68e-15 J

Homework Equations

V = Sq. Rt. ( - ((2)(q)(Vba)) / (m))

The Attempt at a Solution

 

[rock.freak667]

Just sub the values into the formula

 

[mathcrzy]

What is each value? What is q, Vba, and M?

Is M = 1.67e-27 kg ?

And where does the KeV value go?

 

[rock.freak667]

$$E_k=\frac{1}{2}mv^2$$

m=mass of a proton which you have. the eV is just another way to express energy.