Velocity of Proton with 23.0 keV Kinetic Energy

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Homework Help Overview

The discussion centers around calculating the speed of a proton given its kinetic energy of 23.0 keV, with participants exploring the relationship between kinetic energy and velocity in the context of particle physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the kinetic energy formula and question the specific values needed for the calculation, including the charge and potential energy terms.

Discussion Status

The conversation is ongoing, with some participants providing guidance on the formula to use while others seek clarification on the variables involved and their respective units.

Contextual Notes

There is a mention of the conversion between eV and joules, and participants are verifying the mass of the proton as well as the appropriate use of the kinetic energy value in the formula.

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Homework Statement



What is the speed of a proton whose kinetic energy is 23.0 keV?

1 eV = 1.6e-19 J
23 Kev = 23000 eV = 3.68e-15 J

Homework Equations



V = Sq. Rt. ( - ((2)(q)(Vba)) / (m))

The Attempt at a Solution

 
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Just sub the values into the formula
 
What is each value? What is q, Vba, and M?

Is M = 1.67e-27 kg ?

And where does the KeV value go?
 
[tex]E_k=\frac{1}{2}mv^2[/tex]

m=mass of a proton which you have. the eV is just another way to express energy.
 

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