Velocity of shopping cart with given energy/work input

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Homework Help Overview

The discussion revolves around calculating the velocity of a shopping cart after a specified amount of work is done on it, specifically focusing on the relationship between work, kinetic energy, and velocity in a physics context.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to relate work done to kinetic energy and subsequently to velocity. Questions arise regarding the correct application of the kinetic energy formula and the process of deriving velocity from energy input.

Discussion Status

Some participants have provided calculations and expressed confidence in their results, while others are seeking clarification on the methodology used to arrive at those conclusions. There appears to be a productive exchange of ideas regarding the application of physics principles.

Contextual Notes

The problem assumes no friction and requires the use of energy concepts to find velocity, which may lead to various interpretations of the calculations involved.

rhxoehwhfh
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Steve does 50 J of work to push a 3.0 kg shopping cart out of his way. If the cart started from rest, what was its speed immediately after this push? (Assume there was no friction.)

Does anyone know how to calculate velocity with just given energy?... is it calculating the kinetic energy?
 
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rhxoehwhfh said:
Steve does 50 J of work to push a 3.0 kg shopping cart out of his way. If the cart started from rest, what was its speed immediately after this push? (Assume there was no friction.)

Does anyone know how to calculate velocity with just given energy?... is it calculating the kinetic energy?

What is the kinetic energy of the cart after it's been pushed? How do you find velocity from that?
 
since e= mv squared / 2

50 = 3* v(squared) /2

100/3 = v ( squared )

33.33 root = v

5.8 m/s = velocity?...

it this right?
 
That looks good!
 
thank you sir,, have great night
 

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