Velocity of the middle compartment

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The discussion revolves around calculating the velocity of the middle compartment of a train moving on a circular track, where the first and third compartments have velocities v1 and v2, respectively. It is suggested that the middle compartment's velocity can be derived as the average of its neighbors, but there is debate about the correctness of this approach due to the differing directions of v1 and v2. A more detailed expression for the velocity incorporates trigonometric functions and small angle approximations, taking into account the angles associated with each compartment's position on the track. Ultimately, the velocity of the middle compartment is determined to be a function of the velocities of the adjacent compartments and their angular positions. The discussion highlights the complexities involved in analyzing motion on a curved path.
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Hi!

I found this numerical in Finar's Mechanics book and has been unable to do it. Any help would be highly beneficial and appreciated.


A train has three compartments. The first one is moving at a velocity of v1, and the third at a velocity of v2. What would be the velocity of the middle compartment?

Thanks in advance.
 
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I'm not sure why the compartments would be moving at different speeds but if the train is moving on a curved track their velocities would be different. If you assume a circular track and the compartments are evenly spaced then the velocity of the middle compartment will be the average of its neighbors.
 
Hi Tide!

Why would it be the average of the two velocities. Considering that the train is moving in a circular track, then v1 is pointing in one direction, v2 in another, so the final would be the average velocity of v1 and a component of v2... Am I wrong somewhere... please help me to clear this out.

Thank you.
 
deydas said:
Hi Tide!

Why would it be the average of the two velocities. Considering that the train is moving in a circular track, then v1 is pointing in one direction, v2 in another, so the final would be the average velocity of v1 and a component of v2... Am I wrong somewhere... please help me to clear this out.

Thank you.

You can express the velocity as

\vec v = v_0 (-\sin \theta \hat i + \cos \theta \hat j)

The starting point is unimportant on a circular track. If the radius of curvature of the track is much greater than the length of a single compartment then the change in \theta from one to the next is small enough to use the small angle approximation for the trig functions. If the "last car" is at \theta = 0 and the "first car" is at \theta = 2 \alpha then the middle car will be at \theta = \alpha

Keeping first order terms, the respective velocities of the cars are

v_{last} = v_0 \hat j
v_{first} = v_0 (-2 \alpha \hat i + \hat j)
v_{middle} = v_0 (-\alpha \hat i + \hat j)

so the velocity of the middle car is the average of its neighbors. Of course you're free to use the full trig functions if you actually know the relative magnitude of the car length and the track's radius of curvature.
 
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