- #1
Ben1
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Homework Statement
I'm doing an experiment where I'm trying to determine the velocity of a hose when fully turned on using projectile motion. I projected the hose at different angles (15,30,45,60,75,90 degrees) doing 3 tests on each 1. Here is an example I made with the a set of results -
At an angle of 15 degrees from the ground, a hose is turned on. It has a time of flight of 0.4 seconds and a horizontal range of 2.47 meters.
Homework Equations
v=∆x/(cosθt)
The Attempt at a Solution
Horizontal range = v * cos θ * t
2.47 = v * cos 15 * 0.4
v = 2.47 ÷ (cos 15 * 0.4) = 6.392830414 m/s
Is this the TOTAL velocity of the water coming from the hose?
I've asked this question before but somebody told me that this was only the initial velocity, not the actual velocity of the water from the hose and now I'm confused.