Verhulst equation - integration problem

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SUMMARY

The forum discussion centers on the integration of the unforced Verhulst equation, specifically the requirement for the discontinuity in the function g(t) at time t0. The equation is defined as ˙g - g + g² = F₀ δ(t - t₀), where g(t) = 1/(Ae⁻ᵗ + 1). The user seeks to demonstrate that the integrals of g and g² over the interval [t₀ - ε, t₀ + ε] are equal, which is essential for solving the problem. The discussion highlights the need for a solid understanding of integration techniques to tackle this problem effectively.

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Verhulst equation -- integration problem

Homework Statement



Integrate the unforced Verhulst equation over t from t_{0}-\epsilon to t_{0}+\epsilon, take the limit \epsilon \downarrow 0 and show this lead to the following requirement for the discontinuity in g:

\stackrel{lim}{\epsilon \downarrow 0}[g(t,t_{0})]^{t_{0}+\epsilon}_{t_{0}-\epsilon}=F_{0}

Homework Equations



Unforced Verhulst equation:
\dot{g}-g+g^{2}=F_{0} \delta(t-t_{0})

Where:
g(t)=\frac{1}{Ae^{-t}+1}

The Attempt at a Solution



It looks to me that in order to solve this problem I need to show that:
\int^{t_{0}+\epsilon}_{t_{0}-\epsilon}g dt=\int^{t_{0}+\epsilon}_{t_{0}-\epsilon}g^{2} dt

This will not be true of any function g in general, so we must show that it is true for the function in this problem. i.e. Show that:

\int^{t_{0}+\epsilon}_{t_{0}-\epsilon}\frac{1}{Ae^{-t}+1} dt=\int^{t_{0}+\epsilon}_{t_{0}-\epsilon}\frac{1}{(Ae^{-t}+1)^{2}} dt

Is this along the right lines? This is where I get stuck as I'm not very well practiced in integration. I think I can do the one on the left, but am struggling with the one on the right.

Thanks for any help.
 
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Any helpers out there?

Incidentally (for those interested -- and in case you didn't already know) this equation is used in biology to model population dynamics. http://en.wikipedia.org/wiki/Logistic_function

I'm doind an exercise on the application of Green's functions to nonlinear problem.
 

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