Verify Divergence Theorem for V = xy i − y^2 j + z k and Enclosed Surface

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SUMMARY

The discussion focuses on verifying the divergence theorem for the vector field V = xy i − y² j + z k and the specified enclosed surface defined by three parts: (i) z = 0, s < 1, s² = x² + y²; (ii) s = 1, 0 ≤ z ≤ 1; and (iii) z² = a² + (1 − a²)s², 1 ≤ z ≤ a, where a > 1. The left-hand side (LHS) of the divergence theorem was calculated to yield a result of aπ. However, the right-hand side (RHS) integrals for the three surfaces resulted in zero for the first two surfaces, while the third surface's integral proved challenging, even for computational tools like Wolfram Alpha.

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Homework Statement


Verify the divergence theorem for the function
V = xy i − y^2 j + z k
and the surface enclosed by the three parts
(i) z = 0, s < 1, s^2 = x^2 + y^2,
(ii) s = 1, 0 ≤ z ≤ 1 and
(iii) z^2 = a^2 + (1 − a^2)s^2, 1 ≤ z ≤ a, a > 1.

Homework Equations


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[PLAIN]https://upload.wikimedia.org/math/7/b/7/7b759968274f2f43cfaab3ce5672da74.png[PLAIN]https://upload.wikimedia.org/math/a/b/9/ab9fd5a4aaa36e402c98cbd36af3a70d.png

Divergence theorem, although on the RHS I put vector DS = nDS.

The Attempt at a Solution


So I solved the LHS and got the answer to be a*Pi

on the RHS, splitting the 3 surfaces,
(i) got 0 for integral
(ii) got 0 for integral
(iii) staying in cartesians, I have to integrate ((1-a^2)(-x^2 y +y^3 + x^2 +y^2) +a^2)/Sqrt(a^2+(1-a^2)(x^2+y^2) dxdy between -1 and 1 for x and y which even Wolfram can't do.

Spent hours on this please help.
 
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You haven't really said much about what you did. What did you get for \nabla\cdot\vec{V}? What are s and a? Constants? Then "(ii) s= 1, 0\le z\le 1" makes no sense.
 

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