- #1
Duave
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Can someone please tell me if I have solved the problem? Is the math correct? Were the assumptions correct?
Thank you in advance
Show that:
I(B) = 44 uA
I(C) = 4.4 mA
V(CE) = 1.2 V
https://scontent-a.xx.fbcdn.net/hphotos-prn1/t1.0-9/1011057_10151937081760919_165466716_n.jpg
V(B) - V(BE) = V(E)
I(B) = V(B)/R(B)
I(B) = [Beta][I(B)]
The dotted lines were placed for clarity.
Part A
V(B) = 5V
.....
V(BE) = 0.6V
......
V(B) - V(BE) = 5V - 0.6V
........
V(B) - V(BE) = 4.4V
........
R(B) = 100 x 10^3(ohms)
........
I(B) = [4.4V/100 x 10^3]
........
I(B) = 44 uA
......
I(C) = [Beta][I(B)]
.....
I(C) = (100)(44 x10^-6)
.......
I(C) = (4.4 mA)
........
V(C) - [I(C)][R(C)] = V(CE)
........
10V - (4.4 x 10^3(A))(2000(ohms)) = V(CE)
............
10V - (8.8(V)) = V(CE)
......
1.2V = V(CE)
......
Part B
Find Beta
(Beta)[I(B)] = I(C)
.....
I(S){e^(V(BE)/V(T)] -1} = I(C)
.........
I(S){e^(V(BE)/V(T)] -1} = (Beta)[I(B)]
...........
Beta = [I(S)/I(B)]{e^(V(BE)/V(T)] -1}
..........
Beta = [{[V(CC) - V(CE)]/[R(C)]*[e^{V(BE)/VT]}/I(B)]{e^(V(BE)/V(T)] -1}
.............
Beta = [{[V(CC) - V(CE)]/[I(B)][R(C)]
........
Beta = [{[10V - 1.2V]/[44 x 10^-6(A)][2000]
.........
Beta = 100
Thank you in advance
Homework Statement
Show that:
I(B) = 44 uA
I(C) = 4.4 mA
V(CE) = 1.2 V
https://scontent-a.xx.fbcdn.net/hphotos-prn1/t1.0-9/1011057_10151937081760919_165466716_n.jpg
Homework Equations
V(B) - V(BE) = V(E)
I(B) = V(B)/R(B)
I(B) = [Beta][I(B)]
The Attempt at a Solution
The dotted lines were placed for clarity.
Part A
V(B) = 5V
.....
V(BE) = 0.6V
......
V(B) - V(BE) = 5V - 0.6V
........
V(B) - V(BE) = 4.4V
........
R(B) = 100 x 10^3(ohms)
........
I(B) = [4.4V/100 x 10^3]
........
I(B) = 44 uA
......
I(C) = [Beta][I(B)]
.....
I(C) = (100)(44 x10^-6)
.......
I(C) = (4.4 mA)
........
V(C) - [I(C)][R(C)] = V(CE)
........
10V - (4.4 x 10^3(A))(2000(ohms)) = V(CE)
............
10V - (8.8(V)) = V(CE)
......
1.2V = V(CE)
......
Part B
Find Beta
(Beta)[I(B)] = I(C)
.....
I(S){e^(V(BE)/V(T)] -1} = I(C)
.........
I(S){e^(V(BE)/V(T)] -1} = (Beta)[I(B)]
...........
Beta = [I(S)/I(B)]{e^(V(BE)/V(T)] -1}
..........
Beta = [{[V(CC) - V(CE)]/[R(C)]*[e^{V(BE)/VT]}/I(B)]{e^(V(BE)/V(T)] -1}
.............
Beta = [{[V(CC) - V(CE)]/[I(B)][R(C)]
........
Beta = [{[10V - 1.2V]/[44 x 10^-6(A)][2000]
.........
Beta = 100