1. Question Verify that the line with vector equation r = 2i+4j+k + t(-4i-4j-5k) lies wholly in the plane with equation 3x-2y+4z=2. 2. The attempt at a solution r = (2-4t)i + (4+4t)j + (1-5t)k 3(2-4t)-2(4+4t)+4(1-5t) = 2 6-12t-8-8t+4-20t = 2 t = 0 If t = 0, doesn't that mean that the line only intersects with the plane at 2i+4j+k? So then the line does not lie wholly on the plane. So there must be something wrong with this question.