Verifying General Solution of 2D Poisson Equation

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SUMMARY

The discussion centers on verifying that the function u(\vec{x}) := - \frac{1}{2 \pi} \int \limits_{\mathbb{R}^2} \log ||\vec{x} - \vec{y} || f(\vec{y}) d \vec{y} is the general solution to the two-dimensional Poisson equation, represented as Δu = -f, where f is a twice-differentiable function with compact support in C^2_c(\mathbb{R}^2). Participants clarify that the Laplace operator can be applied to u while integrating over y, as x acts merely as a parameter in the integral. This confirms the validity of the proposed solution method.

PREREQUISITES
  • Understanding of the two-dimensional Poisson equation
  • Knowledge of integral calculus and properties of logarithmic functions
  • Familiarity with the Laplace operator and its applications
  • Concept of compact support in function analysis
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  • Study the derivation of solutions to the Poisson equation in multiple dimensions
  • Learn about the properties of the Laplace operator in relation to integrals
  • Explore the concept of compactly supported functions in functional analysis
  • Investigate the application of Green's functions in solving partial differential equations
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Mathematicians, physicists, and engineering students focusing on partial differential equations, particularly those studying the Poisson equation and its applications in various fields.

glmuelle
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Hi

Homework Statement


Verify, that

[tex]u(\vec{x}) := - \frac{1}{2 \pi} \int \limits_{\mathbb{R}^2} \log ||\vec{x} - \vec{y} || f(\vec{y}) d \vec{y}[/tex]

is the general solution of the 2 dimensional Poisson equation:

[tex]\Delta u = - f[/tex]

where [tex]f \in C^2_c(\mathbb{R}^2)[/tex] is differentiable twice and has compact support.

Homework Equations





The Attempt at a Solution




My attempt would be to swap integral and Laplace operator but I know it's wrong to just do that...
Can anyone help me please? Thanks!
Gloria
 
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the Laplace operator is applied with respect to x, and the integration is performed over y -> I think you can swap them ( x is only a parameter inside of the integral)
 

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