Vertical motion and qudaratic equation questions

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Homework Help Overview

The discussion revolves around a problem involving vertical motion and the application of quadratic equations, specifically related to the height of a cricket ball thrown at an initial velocity of 20 meters per second after 1 second.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the substitution of values into the formula for vertical motion, questioning the correct interpretation of the initial velocity and the direction of the throw. There are attempts to clarify the formula used and the variables involved.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the relevant equations. Some guidance has been offered regarding the identification of known values and the appropriate formulas to use, but no consensus has been reached on the final approach or solution.

Contextual Notes

There is a sense of urgency due to a deadline, and participants express confusion about the correct application of the formulas and the direction of the throw. The problem context suggests that the motion is vertical, but there is uncertainty about whether it is upwards or downwards.

jmathew13
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1. a cricket ball is thrown at 20 metres per second . how high will it be after 1 second?

I will subtitute the values in -4.9x1^2 - 20-1



2. any way the formula is -4.9t^2 - ut



3. I think the answer is -4.9-21 :confused:

Sorry for hurry, it is due tomorrow
 
Last edited:
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jmathew13 said:
1. a cricket ball is thrown at 20 metres per second . how high will it be after 1 second?

I will subtitute the values in -4.9x1^2 - 20-1



2. any way the formula is -4.9t^2 - ut



3. I think the answer is -4.9-21 :confused:

Sorry for hurry, it is due tomorrow


Thrown in what direction? ut is not the same as u-t, either
 
sorry then it is -20 so do u know who to do it?/:confused:
the question says it is vertical motion so it should be thrwon vertically
 
Last edited:
jmathew13 said:
1. a cricket ball is thrown at 20 metres per second . how high will it be after 1 second?

I will subtitute the values in -4.9x1^2 - 20-1



2. any way the formula is -4.9t^2 - ut



3. I think the answer is -4.9-21 :confused:

Sorry for hurry, it is due tomorrow


All the equations you have, involve 4 of the following
u,v,s,a,t [some people use d instead of s].
You could start by listing the values for the ones you know, and identifying the one you want, then chose the formula involving those variable, then carefully solve.

Your solution should always start with the formula written out, just to show that you know what you are trying to do.
 
Vertically upwards (probably, given the wording of the question, but I am still not sure), or vertically downwards?

You have initial velocity, time and acceleration. What formula(s) do you know that can link this to position?
 

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