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Very brief explanation please? - Newt 2nd Law w/ Circular Motion

  1. Nov 8, 2009 #1
    Consider a conical pendulum with a weight on it and that makes some angle with the vertical. I am told to find the radial acceleration of the weight and someone showed me how it is solved but I don't understand why:

    I am told to set

    Tsin@ = m(ar) *ar = radial acceleration
    ar = (Tsin@)/m

    I was wondering why it would be T*SIN* instead of T*COS*? Tcos@ would give you the force that is parallel with radial acceleration, Tsin@ gives you a force that is perpendicular to the radial acceleration... Please help me! I don't understand this - only should take a few seconds. Thanks! XP
     
  2. jcsd
  3. Nov 8, 2009 #2
    AHHHH OHHH NEVERMIND! Sorry... *CONICAL* pendulum, lol I was thinking of a regular, 2-D pendulum. I would delete this if I could, but I can't =\ But no need to respond anyone! So silly!!
     
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