Very simple kinematics object accelerates, what is the speed of the object?

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An object starting from rest accelerates at 6.3 m/s² for 2 seconds. To find the final speed, the acceleration is multiplied by the time, resulting in a speed of 12.6 m/s. The discussion highlights confusion over the correct formulas for calculating speed and acceleration. It clarifies that acceleration is the rate of change of velocity over time. Ultimately, the straightforward calculation of speed from constant acceleration is emphasized.
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Homework Statement



Starting from rest, an object accelerates at a rate of 6.3 m/s² for 2 seconds. What is the speed of the object at the end of that time?

Homework Equations



V= d/t

The Attempt at a Solution



If I plug in the 2 seconds to the m/s² then i get

6.3m/4s=1.575

I know i am messing this up, just not sure how
 
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PhilMTSU12 said:

Homework Equations



V= d/t

How is acceleration related to velocity and time?
 
ahh, i had the wrong formula
a = F/m what would be the net force and the mass?
 
PhilMTSU12 said:
ahh, i had the wrong formula
a = F/m what would be the net force and the mass?

while that is correct, it is not relevant here.

So once again, how does acceleration relate to velocity and time i.e. what is the definition of acceleration?
 
the rate of change of velocity as a function of time.

the rate is 6.3m/s², the distance the object travels or speed is what we are looking for and the time is 2 seconds.

if the object has a constant accelerating of 6.3m/s² for 2 seconds I would think you could just multiply 6.3 times 2.
 
PhilMTSU12 said:
if the object has a constant accelerating of 6.3m/s² for 2 seconds I would think you could just multiply 6.3 times 2.

and that would give you the answer
 
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