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- Thread starter Mr Boom
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mfb

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No, this just works with spheres (unless you take a modified electrodynamics in a two-dimensional world).Let's say I have a circle filled with positive charges. Some distance away I have an identical circle filled with negative charges. Since the distribution is uniform in the circles, I can just use the center of the circles as points and calculate the field lines between the two.

Calculate the field along the connection with usual rules for circuits (constant current in the wire). Use some simulation tool for the electric field, as you probably do not find an analytic solution (except for special resistor profiles where the field is unchanged).Now let's say I connect the first circle to the second by a resistor. If the sum of the charges are so large that it is essentially unchanged for some length of time (as in I have constant charges and constant current), how can I calculate the electric field?

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No, this just works with spheres (unless you take a modified electrodynamics in a two-dimensional world).

I was thinking of spheres, yes, but I was trying to just use a 2D example.

Calculate the field along the connection with usual rules for circuits (constant current in the wire). Use some simulation tool for the electric field, as you probably do not find an analytic solution (except for special resistor profiles where the field is unchanged).

This was my question. I'm wondering how the field lines look visually outside the resistor by allowing current to pass. I realize there will also be a magnetic component. Will the lines straighten or become more arched?

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mfb

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mfb

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That won't work.I've plotted the static field lines and I need to superimpose the field due to the resistor?

You can calculate it with a grid, for example, and I would solve for the potential first:

[itex]\phi(x)=0[/itex] for sphere 1, [itex]\phi(x)=1[/itex] for sphere 2, [itex]\Delta \phi = 0[/itex] in free space, and [itex]\phi(x)=f(x)[/itex] with some function f(x) at the resistor. Instead of a 3-dimensional simulation, it is possible to use the symmetry of the problem (if the connection is symmetric) in a 2-dimensional simulation to reduce the required computing power.

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