Vo = (310 Hz / 340 m/s + 0 m/s) * (340 m/s / 342 Hz)Vo = 0.907 m/s

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Homework Help Overview

The discussion revolves around the Doppler Effect, specifically calculating the speed of an approaching vehicle based on the frequency of sound emitted from a stationary source. The original poster presents a scenario involving a car horn and an observer in motion, providing specific frequencies and the speed of sound in air.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct application of the Doppler Effect formula and express confusion regarding the grouping of terms in the equation. There are questions about determining the observer's and source's frequencies and velocities in different scenarios.

Discussion Status

Some participants have offered guidance on the structure of the Doppler Effect equation and the significance of signs based on the relative motion of the source and observer. Multiple interpretations of the problem are being explored, particularly regarding the conditions under which the frequencies change.

Contextual Notes

There is a lack of consensus on the correct application of the Doppler Effect equations, and participants are grappling with the implications of the signs used in the formulas. The original poster expresses uncertainty about their calculations, indicating a need for further clarification.

BuBbLeS01
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Doppler Effect...Ahhhh!

Homework Statement


A student in a parked car honks the horn, which has a `proper' frequency of 310.00 Hz. An observer in an approaching vehicle measures the frequency of the sound to be 342 Hz. Calculate the speed of the approaching vehicle. Use 340 m/s as the speed of sound in air.


Homework Equations


Fo / V + Vo = Fs / V + Vs
Fs = 310 Hz
Vs = 0 m/s
Fo = 342 Hz
Vo = ?
V = 340 m/s


The Attempt at a Solution


Vo = (Fs / V + Vs) * (V / Fo)
I know this is where I am messing up because I am not getting the right answer. Can someone show me where I am going wrong.
 
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Be careful in grouping terms.


One should have a form of the equation as:

f_o\,=\,f_s(\frac{v\pm{v_o}}{v\pm{v_s}}) where subscripts o and s refer to observer and source, respectively, and v is the speed of sound.

Please refer to

http://www.kettering.edu/~drussell/Demos/doppler/doppler.html

Here is a nice tutorial on sound waves

http://www.glenbrook.k12.il.us/gbssci/phys/Class/sound/soundtoc.html
 
Last edited by a moderator:
What if I am looking for the speed. And for this one how I do I determine what is the observer F and V and the source F and V?

A person standing close to a railroad crossing hears the whistle of an approaching train. He notes that the pitch of the whistle drops as the train passes by and moves away from the crossing. The frequency of the approaching whistle is 517 Hz, and drops to 494 Hz after the train is well past the crossing. What is the speed of the train? Use 340 m/s for the speed of sound in air.
 
Does anyone know how to do this?
 
so if we want to find the Velocity we can do...
(Fs +/- Fo) / (Fs +/- Fo) * V = Vs
and...
(Fo +/- Fs) / (Fo +/- Fs) * V = Vo

how do I know if its +/-? I know it depends on if the source is approaching or receding but what sign corresponds to which?
 
BuBbLeS01 said:
What if I am looking for the speed. And for this one how I do I determine what is the observer F and V and the source F and V?
In the equation provided by Astronuc, V is the speed of sound, Vo is the speed of the observer, and Vs is the speed of the source. Fs is the frequency of the source and Fo is the observed frequency.

BuBbLeS01 said:
how do I know if its +/-? I know it depends on if the source is approaching or receding but what sign corresponds to which?
If source and observer approach each other, Fo > Fs; if they separate, Fo < Fs.
 

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