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Zahid Iftikhar

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In summary, at resonance, the voltage across R, L, and C in a series resonance circuit can be larger than the source voltage, which is counter-intuitive and does not happen in DC circuits. This can be compared to a swinging weight on a rope, where small periodic forces can generate a large swing displacement. In time-varying magnetic fields, there is no potential for the electric field due to Faraday's Law. A helpful analogy for this phenomenon is to think of pushing a swinging weight with a small force and displacement. Further information on this topic can be found in the lecture on EM field theory provided in the given webpage.

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Zahid Iftikhar

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berkeman

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As long as the losses are low for the swinging weight, it takes very small repetitive/resonant forces and small pushes from your fingertip to make it build up a large swing displacement -- much larger than the small periodic push amplitude of your fingertip...

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$$\vec{\nabla} \times \vec{E}=-\frac{1}{c} \partial_t \vec{B}.$$

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Zahid Iftikhar

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Thanks. I need more help on this please.vanhees71 said:

$$\vec{\nabla} \times \vec{E}=-\frac{1}{c} \partial_t \vec{B}.$$

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https://itp.uni-frankfurt.de/~hees/physics208.html

The voltage across R, L, and C in an RLC series circuit is the voltage drop across each individual component due to the flow of current. This voltage drop is caused by the resistance, inductance, and capacitance of each component. On the other hand, the AC voltage source is the alternating voltage that is applied to the circuit and is responsible for driving the flow of current through the circuit.

The voltage across R, L, and C in an RLC series circuit changes with respect to frequency due to the impedance of each component. At low frequencies, the impedance of the inductor is low, causing most of the voltage to drop across the inductor. At high frequencies, the impedance of the capacitor is low, causing most of the voltage to drop across the capacitor. At the resonant frequency, the impedance of the inductor and capacitor cancel each other out, resulting in a higher voltage drop across the resistor.

When the circuit is in resonance, the voltage across R, L, and C is at its maximum value. This is because the impedance of the inductor and capacitor cancel each other out, resulting in a lower total impedance. This lower impedance allows for a higher flow of current, resulting in a higher voltage drop across the resistor.

The phase difference between the voltage across R, L, and C and the AC voltage source changes with frequency in an RLC series circuit due to the phase shift caused by the inductor and capacitor. At low frequencies, the inductor causes a phase shift of 90 degrees, while the capacitor causes a phase shift of -90 degrees. At the resonant frequency, these phase shifts cancel each other out, resulting in a phase difference of 0 degrees.

When the resistance in the circuit is increased, the voltage across R, L, and C decreases. This is because the increased resistance causes a higher voltage drop across the resistor, resulting in less voltage available for the inductor and capacitor. This also affects the resonant frequency of the circuit, causing it to shift to a lower frequency.

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