# Voltage Drop across Capacitor?

## Main Question or Discussion Point

Hi all,

Here's the problem!

I am attempting to create a leakage current test suite. Basically it centers around cutting the voltage reference supply to a capacitor and measuring the voltage drop. Similar to the one in the attachment.

I figured that to determine the drop it would be a simple case of V at start minus V after time delay.

However a colleage told me that because of the exponential decay of capacitors this simple equation wouldn't be enough to accuratly determine the voltage drop.

Any ideas?

Thanks!

- Si

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Redbelly98
Staff Emeritus
$$V_t = V_{ref} \ e^{-t/(RC)}$$