I know how capacitors behave when connected to a dc voltage supply. For a simple RC circuit we have the time constant thing come up into the equations and then we can find the exponential fall of voltage and currents.(adsbygoogle = window.adsbygoogle || []).push({});

but what I don't get is the what would be the behavior of the same in a ac circuit. Can we determine it using juts the normal equations? If so then please confirm the result I get...

V(c) = V*sin(WT)/(C*Z*W)

where V(C) is the voltage across capacitor, VcosWT is the voltage of ac source. C is capacitance. Z is the impedance of RC circuit and W is the frequency. (given initial charge on the capacitor is 0)

Also please help me with the following extension of the problem: What difference would come up if we ground the circuit in the following manner. R and C are same, V is an AC source of waveform VcosWT...

Thanks...

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# Capacitor and their behavior in AC

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