- #1

null void

- 102

- 1

Can i first regard the voltage contributed by a very small charge in this expression:

dV = κ(λ dx)/√(x

^{2}+ y

^{2}) ...where κ = 1/4Ωε

v = κ(λ) ∫ dx/√(x

^{2}+ y

^{2})

= κλ ln( √(x

^{2}+ y

^{2}+ x)

If the integral start from -∞ to +∞ of x, the formula does not converge, but my logic tells me that the charge of the wire at infinity doesn't affect the voltage at point p. Does this mean my approach is wrong?