Voltage Regulator, Battery resistance, current

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SUMMARY

The discussion centers on the behavior of a 5V voltage regulator connected to a 9V power source and its response to increased input voltage. It is established that the output voltage remains constant at 5V regardless of whether the input is 9V or 12V, provided the input voltage is within the regulator's acceptable range. The output current is determined by the load and the internal resistance of the battery, which remains constant. Therefore, increasing the input voltage does not increase the charging current to the battery; instead, excess voltage is dissipated as heat by the regulator.

PREREQUISITES
  • Understanding of voltage regulators and their function
  • Knowledge of Ohm's Law and electrical resistance
  • Familiarity with battery characteristics, including internal resistance
  • Basic principles of electrical power dissipation
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  • Research the specifications and limitations of linear voltage regulators
  • Learn about power dissipation in voltage regulators and thermal management
  • Explore the impact of load variations on output current in voltage regulation
  • Study battery charging characteristics and how they relate to voltage and current
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Electrical engineers, hobbyists working with power supplies, and anyone involved in battery charging systems will benefit from this discussion.

ramonegumpert
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Dear Experts

Lets say I have a power source of 9 volts.
A 5v output voltage regulator is connected to this power supply.
So, input 9 volts, output is regulated to 5volts constant.
the output pin is connected to a battery with has a constant internal resistance.

Does this mean, because the resistance of battery and the charging voltage is constant, the charging current going into the battery will not increase even when the power source is increased say from 9 volts to 12 volts?

So, my question is can a voltage regulator giving constant 5 volt output charge with higher current when the source voltage is increased?

Thanks for reading.

Best regards
Ramone
 
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The point of the voltage regulator is to provide a constant output (i.e. regulate the output to within certain tolerances) over a range of input voltages. So, even with a 12 volt input, the output of the regulator is still 5 V, (assuming that both 9 V and 12 V are within the range of acceptable inputs for your regulator). So, regardless of input voltage, it's still 5 V at the output, which means that the same thing will happen when you connect the thing to a battery in both cases.

A voltage regulator steps down voltage by basically wasting power. So, with a higher voltage input, more energy will be wasted as heat in order to step down to 5 V. That's about it.
 
Hello Cepheid

Thank you for your response.
To finalise, the output current from voltage regulator cannot be increased as the battery resistance is constant.

regards
Ramone
 
ramonegumpert said:
Hello Cepheid

Thank you for your response.
To finalise, the output current from voltage regulator cannot be increased as the battery resistance is constant.

regards
Ramone

That's correct for your example, but it's potentially misleading.

If the load needs 100mA, the regulator gives it 5 volts at 100mA. If the load changes, the regulator current follows it (within design limits.) You can double the voltage going into the regulator, but if the load doesn't change, the current doesn't change.

As cepheid said, the higher voltage is simply dissipated as heat by the voltage regulator.

(Of course, like all electrical circuits, if you supply higher than its rated voltage, bad things tend to happen.)

ETA: Look at the information panel on some power supplies -- such as the charger for your phone. Mine says:
Input: 100-240v, 50/60Hz, 0.1A
Output: 5.9v DC, 375mA​
You can see that a wide range of input voltage has no effect on the output.
 
Last edited:
Thank you very much Mr Pantaz :)
 

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