Volume between cylinder and ellipsoid

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SUMMARY

The discussion focuses on calculating the volume bounded by a cylinder defined by the equation \(x^{2}+y^{2}=4\) and an ellipsoid given by \(4x^{2}+4y^{2}+z^{2}=64\). The user successfully reparameterized the surfaces using the equations \(x=2s\cos(t)\), \(y=2s\sin(t)\), and \(z=-8(s^{2}-4)\), leading to the integral \(\int\int_{D}(S-M)dA\). The final computed volume is \(32\pi\). The discussion emphasizes the importance of clarity in defining the volume of interest and suggests using cylindrical coordinates for simplification.

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  • Familiarity with double integrals
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  • Ability to perform reparameterization in multivariable calculus
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Homework Statement


I have two surfaces, a cylinder and an ellipsoid. I want to find the volume bounded by those two surfaces. The sufaces are:
S
x^{2}+y^{2}=4

and
M
4x^{2}+4y^{2}+z^{2}=64

Homework Equations



reparameterize it to get it in the form:

\int\int_{D}(S-M)dA

If you do this and reperameterize it, you need to multiply it by the determenant of the x and y values.

The Attempt at a Solution



I reperameterized the intersection of both curves to be:

x=2s*cos(t)
y=2s*sin(t)
z=-8(s^{2}-4)

so using that integral form S - M
I got:

\int\int_{D}-3x^{2}-3y^{2}-z^{2}+60 dA

plugging in the reperamiterization I got:

=\int\int_{R}-3(2scos(t))^{2}-3(2ssin(t))^{2}+16s^{2}-4|X_{s}*Y_{t}-X_{t}*Y_{s}| dA

=\int\int_{R}(4s^{2}-4)(4s) dA

=16\int_0^1\int_0^{2\pi}(s^{3}-s) dtds= 32\pi

now I'm not sure if what I've done was correct, but can someone help me to make sure if it is, whether it be by this method or another method.

thanks.
 
Last edited:
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First, the "volume bounded by those two surfaces" isn't very clear. Do you mean the volume inside of both? I am guessing that is what you want. If so you are making the problem way too complicated. Draw a picture. The xy domain is the interior of a circle. Use cylindrical coordinates.
 

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