Volume by cross-section: ellipse and equilateral triangle cross sections?

  1. Volume by cross-section: ellipse and equilateral triangle cross sections??

    1. The problem statement, all variables and given/known data

    The base of a solid is the region bounded by the ellipse 4x^2+9y^2=36. Find the volume of the solid given that cross sections perpendicular to the x-axis are:
    a) equilateral triangles
    b) squares


    2. Relevant equations



    3. The attempt at a solution

    So I'm not really sure how ellipses work.. how can I sketch this ellipse?
    Beyond that.. I try to calculate the area of the triangle and then integrate in terms of y so the base is changing according to the ellipse curve.

    I write the ellipse as:

    y = +/-sqrt((-4/9)x^2 + 4)

    So the base of the triangle is 2(sqrt((-4/9)x^2 + 4))
    And has that as the length on all side since it is equilateral.
    Then I try to find the height using Pythagoras and get

    h = +/-sqrt((-4/3)x^2 + 12)

    Then now I have the area of the triangle as (1/2)bh, which is =

    A = (1/2)(2(sqrt((-4/9)x^2 + 4)))(sqrt((-4/3)x^2 + 12))

    Then I can integrate in terms of x.. does that look correct so far?
     
  2. jcsd
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