Calculating Volume of Described Solid with Equilateral Cross-Sections

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SUMMARY

The volume of the solid with a triangular base defined by vertices (0, 0), (5, 0), and (0, 5) and equilateral triangular cross-sections perpendicular to the y-axis is calculated using the correct line equation. The correct equation for the line segment between (5, 0) and (0, 5) is x = 5 - y. The area of the cross-section is given by A(y) = (1/2)(5 - y)², leading to the integral for volume V = ∫ A(y) dy from 0 to 5. The initial error stemmed from using the incorrect line equation, which has been clarified in the discussion.

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  • Ability to derive equations of lines from given points
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  • Study the calculation of areas for different types of cross-sections
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Homework Statement



The base of S is the triangular region with vertices (0, 0), (5, 0), and (0, 5). Cross-sections perpendicular to the y-axis are equilateral triangles.
Find V of described triangle.

Homework Equations





The Attempt at a Solution


I first wrote the equation of the line in terms of x (x = 4-y), which is the base. Since we are dealing with an equilateral triangle the area of the cross section would be A(y)= ((4-y)^2)/2 and so the integral to calculate the volume is A(y)dy from 0 to 4.
Since I am arriving at the supposedly wrong answer, what am I missing?
 
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Nicolaus said:

Homework Statement



The base of S is the triangular region with vertices (0, 0), (5, 0), and (0, 5). Cross-sections perpendicular to the y-axis are equilateral triangles.
Find V of described triangle.

Homework Equations





The Attempt at a Solution


I first wrote the equation of the line in terms of x (x = 4-y), which is the base.
I don't see where your equation comes from. What's the equation of the line between (5, 0) and (0, 5)?
Nicolaus said:
Since we are dealing with an equilateral triangle the area of the cross section would be A(y)= ((4-y)^2)/2 and so the integral to calculate the volume is A(y)dy from 0 to 4.
Since I am arriving at the supposedly wrong answer, what am I missing?
 
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It's a typo; meant 5-y. I figured out the problem. Thanks for your interest in helping.
 

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