- #1

vikasagartha

- 15

- 0

[itex] E_{out} - E_{in} = \frac{\sigma_{free}}{\epsilon_0}[/itex]

However, in the case of a uniform, circular charge density,

[itex]\vec{E_{in}} = \frac{\rho r}{3\epsilon_0}\hat{r}[/itex]

[itex]\vec{E_{out}} = \frac{\rho R^3}{3\epsilon_0 r^2}\hat{r}[/itex]

But this electric field is continuous @ r=R. If a volume has a charge density, doesn't it have to have some sort of a surface charge? How can there be no surface charge?