Volume of 1 Mole Gas at 1atm, 273.15K

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SUMMARY

At 1 atm pressure and 273.15K, 1 mole of an ideal gas occupies a volume of 22.4 liters, as derived from the ideal gas law PV = nRT. The calculation requires consistent units; using the ideal gas constant R in appropriate units is crucial. The discrepancy in the initial calculation arose from using R = 8314 instead of the correct value for the units used. The correct value for R when using liters and atmospheres is 0.0821 L·atm/(K·mol).

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Knowledge of unit conversions between SI and non-SI units
  • Familiarity with the gas constant R and its various values
  • Basic algebra for manipulating equations
NEXT STEPS
  • Learn about the different values of the gas constant R for various unit systems
  • Study unit conversion techniques between SI units and common laboratory units
  • Explore the concept of ideal gases versus real gases
  • Investigate the implications of temperature and pressure on gas behavior
USEFUL FOR

Chemistry students, physics enthusiasts, and anyone studying thermodynamics or gas laws will benefit from this discussion.

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What volume does 1 mole of gas occupy at 1 atm pressure and 273.15K?

PV = nRT so V =nRT/P

V = (1)(8.314)(273.15)/1

Im getting 2270.96, the answer is ment to be 22.4L, what am i doing wrong?

P= 1
V= ?
n= 1
R= 8314
T= 273.15K
 
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You need to use a consistent set of units. Atm and L are not SI units. The SI units for pressure are Pascals (Pa), and for volume m^3. Look these up.
 
have it now, thanks
 

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