Volume of 1 Mole Gas at 1atm, 273.15K

[db1]

What volume does 1 mole of gas occupy at 1 atm pressure and 273.15K?

PV = nRT so V =nRT/P

V = (1)(8.314)(273.15)/1

Im getting 2270.96, the answer is ment to be 22.4L, what am i doing wrong?

P= 1
V= ?
n= 1
R= 8314
T= 273.15K

 

[phyzguy]

You need to use a consistent set of units. Atm and L are not SI units. The SI units for pressure are Pascals (Pa), and for volume m^3. Look these up.

 

[db1]

have it now, thanks