(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

one mole of an ideal gas takes up 0.0225m3 at 0 degrees celsius and 1.01x10(5) pascals. (calculated)

hence, calculate the volume of 1 mole of air (ideal) at an altitude of 15km above sea level.

average molecular mass of air = 29 amu.

T @ altitude of 15km = 0 degrees C.

2. Relevant equations

I used pv=nrt for the first part.

another equation i can find is

M = m N A

where M is the mass of the mole in kg, m is the atomic mass unit in kg, N is the atomic mass, and A is avogadros constant.

3. The attempt at a solution

volume of a mole of air can be calculated using pv=nrt, rearranged for v which is v=nrt/p.

however, i have no idea how to bring the altitude into it!

thanks for help!

Edit: Perhaps equation P = P0 exp (-mgy/k(b) t)?

where m = average molecular mass in kg, g = acceleration due to gravity, y = altitude in m, kb is boltzmanns constant and t is temperature?

but i'm not sure where to find volume.

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# Homework Help: Volume of a mole of air 15km above sea level

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