Volume of a solid bound by region work shown

[johnq2k7]

The base of a solid is the region bounded by y= 2*sqrt(sin(x)) and the x-axis, with x an element of [0, (pi/2)]. Find the volume of the solid, given that the cross sections perpendicular to the x-axis are squares.

Work Shown:

cross sections are squares:

therefore A(x) is not equal to Pi*r^2 rather l^2

therefore A(x)= [sqrt(sin(x)]^2

therefore integral of A(x)dx of x-values from 0 to Pi/2 should provide the answer

I think my approach is wrong and my integral for A(x) dx is wrong as well please help!

 

[tiny-tim]

Hi johnq2k7!

(have a pi: π )

Seems ok (except you seem to have droppoed the original 2) …

the general rule is to specify the slices you're dividing it into … in this case, slices of thickness dx and area y².