Volume of a sphere under a linear transformation R3->R4.

In summary, the problem is to find the 3-dimensional volume of the image of a unit sphere under a linear transformation T, given a standard matrix A and the determinant values of A multiplied by each basis vector. The solution involves using the determinant of a matrix as a scaling factor for volume change, and a potential formula of Ʃ(det(Ai))2 for the volume based on determinants.
  • #1
BluFoot
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Homework Statement


So there's a linear transformation T: ℝ3 → ℝ4, standard matrix A that satisfies

det(A e1) = 5, det (A e2) = 4, det (A e3) = 5 and det (A e4) = 5

If S is the unit sphere, find the 3-dimensional volume of T(S).

Homework Equations


Volume of sphere = 4/3 * pi * r^3
Volume based on determinants = det(ATA)


The Attempt at a Solution


I know the determinant of a matrix can be seen as the scaling factor for the volume change of a transformation. So the answer will be 4/3 * pi * (something). The (something) will probably be some kind of combination of the determinants above (5,4,5,5), but I have no clue how to find its value. I have spent hours on this question, it's driving me crazy. Help!
 
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  • #2
Thinking about the ℝ1 → ℝ2 suggests a root-sum-squares relationship. Can't see how to generalise it yet.
 
  • #3
Have now proved the following for both ℝ1 → ℝ2 and ℝ2 → ℝ3, but still don't see how to prove it in general.
Denoting the square matrices formed by appending the basis vectors as Ai, det(ATA) = Ʃ(det(Ai))2.
 

1. What is the formula for finding the volume of a sphere under a linear transformation R3->R4?

The formula for finding the volume of a sphere under a linear transformation R3->R4 is V = (4/3)πr^3, where r is the radius of the sphere.

2. How is the formula for finding the volume of a sphere under a linear transformation R3->R4 different from the traditional formula for volume of a sphere?

The formula for finding the volume of a sphere under a linear transformation R3->R4 is different from the traditional formula (V = (4/3)πr^3) because it takes into account the additional dimension (R4) that is being transformed to. This results in a larger volume compared to the traditional formula.

3. Can the volume of a sphere under a linear transformation R3->R4 ever be negative?

No, the volume of a sphere under a linear transformation R3->R4 cannot be negative. The volume of a sphere is always a positive value, regardless of the dimensions it is being transformed to.

4. How does the transformation from R3 to R4 affect the volume of a sphere?

The transformation from R3 to R4 increases the volume of a sphere. This is because the additional dimension adds more space for the sphere to occupy, resulting in a larger volume.

5. Can the volume of a sphere under a linear transformation R3->R4 exceed the traditional volume of a sphere?

Yes, the volume of a sphere under a linear transformation R3->R4 can exceed the traditional volume of a sphere. This is because the transformation adds an extra dimension, resulting in a larger volume compared to the traditional formula.

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