Volume of intersection of spheres

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Homework Help Overview

The discussion revolves around finding the volume of the intersection of two spheres, each with a radius of 2, where the center of each sphere lies on the surface of the other. The problem is situated within the context of calculus, specifically in a Calculus 2 class.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using volumes of revolution and the washer method for integration. There are attempts to determine the points of intersection and concerns about the correctness of the integration approach. Questions arise regarding the geometry of the intersection and whether the cross-sections are circles or ellipses.

Discussion Status

Some participants have provided guidance on the integration range and confirmed that the cross-sections are circles. There is an ongoing exploration of the volume calculation, with some participants expressing uncertainty about the geometry involved and the correctness of their approaches.

Contextual Notes

Participants mention the need to consider the geometry of the intersection and the implications of using the washer method. There is also a reference to the specific range of integration used in the calculations.

icosane
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Homework Statement


Find the volume of the intersection of two spheres of radius 2, give that the center of each sphere lies on the surface of the other.

The Attempt at a Solution



I was trying to do this problem with volumes of revolution. I drew two circles, one with a center at -1, the other with a center at 1. I found the point of intersection on the y-axis to be + and - root3. I was going to use the washer method, rotating the line y = (4-(x+1)^2)^(1/2) over the x-axis but I can't integrate that expression. I'm also unsure if that would even give the correct answer. Any tips on how to approach the problem? This is for a calc 2 class btw, so it shouldn't be especially difficult.
 
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icosane said:

Homework Statement


Find the volume of the intersection of two spheres of radius 2, give that the center of each sphere lies on the surface of the other.

The Attempt at a Solution



I was trying to do this problem with volumes of revolution. I drew two circles, one with a center at -1, the other with a center at 1. I found the point of intersection on the y-axis to be + and - root3. I was going to use the washer method, rotating the line y = (4-(x+1)^2)^(1/2) over the x-axis but I can't integrate that expression. I'm also unsure if that would even give the correct answer. Any tips on how to approach the problem? This is for a calc 2 class btw, so it shouldn't be especially difficult.

Woops just realized that I would be taking the integral of y^2 so that square root sign doesn't mess up my ability to integrate. Still though, will I get the correct answer if I find that volume and multiply it by two? My concern is that I'm overlooking something about the geometry of the intersection. Like it seems like the volume would be a sum of the area of ellipses, not circles. Yet I don't know how I would end up with an elliptical equation from two intersecting spheres? Help please.
 
What range of x are you using when integrating using washers under the curve y=(4-(x+1)^2)^(1/2)? If you've got the right range, yes then you can just double that volume. The cross-sections of your volume perpendicular to the x-axis are circles, not ellipses. I don't think you are missing anything.
 
Dick said:
What range of x are you using when integrating using washers under the curve y=(4-(x+1)^2)^(1/2)? If you've got the right range, yes then you can just double that volume. The cross-sections of your volume perpendicular to the x-axis are circles, not ellipses. I don't think you are missing anything.

The range I used is just x = 1 to 0...
 
I used x=0 to x=1, but yes, that seems fine.
 
Did anyone try this and get 8/3 * pi ??
 
icosane said:
Did anyone try this and get 8/3 * pi ??

That's not what I get. Can you show how you got that?
 

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