Volume of revolution at line x=-4

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SUMMARY

The discussion focuses on calculating the volume of a solid formed by rotating the region bounded by the curves y=0, y=sin(6x), x=6, and x=0 around the line x=-4. The cylindrical method is applied, specifically using the formula for volume as circumference times thickness times height. The correct integral setup is confirmed to be 2*pi*(4-x)dx*sin(6x), which accounts for the distance from the axis of rotation to the curve.

PREREQUISITES
  • Understanding of the cylindrical method for volume calculation
  • Familiarity with the sine function and its properties
  • Knowledge of definite integrals and their applications
  • Basic skills in setting up integrals for geometric problems
NEXT STEPS
  • Study the cylindrical method in detail for various geometric shapes
  • Explore the properties of the sine function and its applications in calculus
  • Learn how to set up and evaluate definite integrals for volume calculations
  • Investigate other methods of finding volumes of revolution, such as the disk and washer methods
USEFUL FOR

Students studying calculus, particularly those focusing on volume calculations and the methods of integration. This discussion is beneficial for anyone seeking to understand the application of the cylindrical method in real-world scenarios.

~Sam~
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Homework Statement



Find the volume of the solid obtained by rotating the region bounded by the curves y=0,y=sin(6x),x=6,x=0 about the axis x=−4.


Homework Equations



cylindrical method? circumference*thickness*height


The Attempt at a Solution



So I'm not sure how to write the integral when it rotates along the line x=-4 ..would it be like 2*pi*(-4+x)dx*sin(6x)? or 2*pi*(4-x)dx*sin(6x)? Or something completely different?
 
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